model 3 fraction of numbers Practice Questions Answers Test with Solutions & More Shortcuts

Question : 26

A boy was asked to find the value of $3/8$ of a sum of money. Instead of multiplying the sum by $3/8$ he divided it by $3/8$ and then his answer exceeded by Rs.55. Find the correct answer ?

a) Rs.1,320

b) Rs.64

c) Rs.24

d) Rs.9

Answer: (c)

Let the amount be Rs.x

According to question,

$8/3$x - $3/8$x = 55

= $\text"64x – 9x"/24$ = 55

= $\text"55x"/24$ = 55 (or), x = Rs.24

Question : 27

$1/5$of a number exceeds $1/7$ of the same number by 10. The number is :

a) 200

b) 175

c) 150

d) 125

Answer: (b)

Let the number be x.

∴ According to question,

$x/5 – x/7$ = 10 ⇒ ${7x – 5x}/35$= 10

⇒ $2/35$= 10

⇒ x = ${10 × 35}/2$= 175

Question : 28

A fraction having denominator 30 and lying between $5/8$ and $7/11$ is–

a) $21/30$

b) $20/30$

c) $19/30$

d) $18/30$

Answer: (c)

$5/8$ = 0.625; $7/11$ = 0.636;

$20/30$ = 0.666…; $19/30$ = 0.633…;

Question : 29

Express 45 minutes as the fraction of one day.

a) $1/24$

b) $1/60$

c) $1/32$

d) $1/40$

Answer: (c)

1 day = 24 × 60 minutes

Required fraction = $45/{24 × 60} = 1/32$

Question : 30 [SSC CGL Prelim 2004]

$1/10$ of a rod is coloured red, $1/20$ orange, $1/30$ yellow, $1/40$ green, $1/50$ blue, $1/60$ black and the rest is violet. If the length of the violet portion of the rod is 12.08 metres, then the length of the rod is

a) 30 m

b) 20 m

c) 18 m

d) 16 m

Answer: (d)

Let the length of the rod be x metres.

According to the question,

$x – (x/10 + x/20 + x/30 + x/40 + x/50 + x/60)$ =12.08

$x[1 – ({60 +30 + 20 + 15 + 12 + 10}/600)]$ = 12.08

$x(1 - {147}/600)$ = 12.08

$x({600 - 147}/600)$ = 12.08

$x × 453/600$ = 12.08

$x = {12.08×600}/453$ =16 m.

IMPORTANT quantitative aptitude EXERCISES

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